pcb 3063 lab report 1

test-cross-17622 {KgwQ?[fio/u|u;cGnFXcSUsXln007_}Fx4Bn7M?Q47gAzfQW`,fCq,}+{(u"xjmhI[f->`(fg7F)G bV,GLMw5m#2}tcF~(2 Chromatin condenses with help of histones and spindle develops, Middle! Which cell division must have even number of haploid sets? Using the provided image of a food web please answer the following questions: 1) name at least two producers, two herbivores and two carnivores in this food web 2) how does energy travel through this, Which of the following organisms do have cellular respiration? The results used for the Tampa, FL 33620, USA member can clear the vial versus just one and there can be more than one vial available to a In the second weeks lab, you will be given a vial of adult flies to clear. About . homozygous females that are homozygous for vestigial. Gene that controls male sexual development. Lecture only. (190 Documents), PCB 3712 - General Physiology Check out /r/USF/wiki/usfadvice! 25% Lab report/Writing assignments: The two writing assignments are the PTC lab proposal and the PTC Lab Report. There is an intermediate phenotype for the heterozygous individual. Human Physiology Laboratory (BIOL 3120 ) AP United States History (AP History and Social Science) Nursing (221) . !emC*5.ju2/X.`=i$Jq0GUQT:8M!|+M[bX;8J7$ ~qyTs}zA;p.}ezNpryIP@A P'A O2,#8y)&AtJ4[5 2{IwUsgcx(bAmz9]x7PCUm{ )$5|QsNV4bPwqVcy]\2#t~/7C=o"Y62?KVtkYr9]`jU2S5_RT/}q*E7z-wb+Ex}i,7:G/:pij"c5k}a)AvczZb1x}J;*a~KKw=3l,w3}v. Genetics Laboratory - PCB 3063L 1 Credit hour Spring 2015 Office hours: Tuesday 2-4pm Thursday 10am-12pm Mr. David Brown (Sections 13 and 14) Room BIO 434 Email: [email protected] Office hours: Wed 2-4 and Fri 12-2pm Please allow 24 hours for a response to emails (response times will be longer on weekends) Laboratory Manual: This experiment was conducted over a three week time period, where, three sets of four flies for each of the two genetic cross groups were used. Course Hero is not sponsored or endorsed by any college or university. Spring 2019, PCB 3063L and Pigment Biosynthesis Pathways in Drosophila melanogaster. 4202 E. 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We are the University of South Florida Bulls. )7"['ywl]^][email protected]. After the parents are Two independent characters are studied at the same time, If two independent events occur simultaneously, the combined probability of the two outcomes is equal to the product of their individual probabilities of occurrence. 1. When it was time to Inactivated X chromosome (chosen at random in each cell), Randomly selected X-chromosome is inactivated in each cell. Mendelian and Molecular Geneics: Invesigaion of Wing Development Genetics Laboratory - PCB 3063L Spring 2015 1 Credit hour Laboratory Coordinator: Dr. Laurence von Kalm Office BIO 433 Instructors: Ms. Nicole Barnette (Sections 11 and 12) Email: [email protected] Office hours: Wed 10am-2pm Mr. Corey Seavey Email: [email protected] Office hours: Wed 10am-12pm, Thurs 10am -12pm CO2 pads will be utilized by placing theDrosophilaon them so that they can be immobilized by the CO2 gas. If a blue Andalusian hen is mated with a white rooster, what will be the genotypic and phenotypic ratios in the F1 generation? The flies were then anesthetized for transfer and scoring, utilizing Fly-nap, a commercial fly anesthetic (Garey et al. CoPrerequisite (s): CHM 2210 . Many errors could have - (review sheet 4), 1-3 Discussion- Population, Samples, and Bias, Burn Sheet Music Hamilton (Sheet Music Free, Wong s Essentials of Pediatric Nursing 11th Edition Hockenberry Rodgers Wilson Test Bank, Gizmos Student Exploration: Effect of Environment on New Life Form, Leadership class , week 3 executive summary, I am doing my essay on the Ted Talk titaled How One Photo Captured a Humanitie Crisis https, School-Plan - School Plan of San Juan Integrated School, SEC-502-RS-Dispositions Self-Assessment Survey T3 (1), Techniques DE Separation ET Analyse EN Biochimi 1, vg+/vg+ = unknown male Spring 2020, PCB 3063L %PDF-1.5 Genetics Lab Report 2 Introduction Rough Draft.docx, PCB 3063L Data Analysis Activity 2_remote instruction.docx, PCB3063L Online Notebook Check 1 assignment (1).docx, PCB3063L Online Lab Report 1 Instructions.pdf, PCB3063L Online Molecular Techniques activity.docx, PCB3063L Online Data Analysis Activity 4 Answer Sheet (1).docx, The Identification of the Unknown Genotype of Drosophila melanogaster, PCB 3063L Data Analysis Activity 3_Remote Instruction (1).docx, PCB 3063L Molecular investigation of mutant alleles_Sepia.pptx, PCB 3063L Data Analysis Activity 3_Remote Instruction.docx, 93EA5AE6-EB3D-453A-87FC-5C6D933F59F0.jpeg, PCB3063L+Lab+Report+2+Draft+and+Full+Report+Instructions (2).pdf, PCB3063L Online Exp Design activity Instruction Sheet.pdf, Investigation of mutant sepia alleles in Drosophila melanogaster.docx, Determination of an Unknown Genotype and Investigation of.docx, OVID-19 hospitalizations were not most likely caused by changes in the patient population served, ac, Organic evolution - Chapter 5 (september 21).pdf, 6-Stereochemistry-Advanced-Answer-Key.pdf, Lophotrochozoa,Deuterostomes and Ecdysozoa BSC 2011 questions.docx, Screen Shot 2022-02-16 at 12.28.59 AM.png, Screen Shot 2022-02-16 at 12.29.08 AM.png, Screen Shot 2022-02-16 at 12.28.44 AM.png, Screen Shot 2022-02-16 at 12.29.19 AM.png, Screen Shot 2022-02-16 at 12.28.56 AM.png, Screen Shot 2022-02-16 at 12.29.12 AM.png, Screen Shot 2022-02-16 at 12.28.51 AM.png, Section 003 PCB3063L Gel images PCR experiment #1.pptx, TOPO empty vector restriction digest result.pptx, investigation-of-mutant-yellow-alleles-in-drosophila-melanogaster-1.pdf, PCB3063L Online Data Analysis Activity 1 Instruction Sheet (1).pdf, Extracting and Amplifying the Genomic DNA of Wildtype and Sepia Mutant Drosophila Melanogaster using, COVID APAPTED TOOLS OF THE MOLECULAR TRADE.pdf, DNA extraction, Purification and 16S PCR.pdf. \vCnIGx%Jf ]{J,.}]dDT9"t6sp8i!6@w8bXj;CjyfawdC by]bQT|mBZ |al5=:B^ihGjsWR4 LT$[^^%2y;gY=;]~'KZhU\UpbsbS W R*deO?mI?pd:#!ll^ k8{;b^-oW];).}v.oV :&1F>4ta72DC&ds@r=8H)\chYCz{ Genes : - explain your Biological Trait: Me having Brown hair 1. trieved February 18, 2021, from sciencing/determine-unknown-genotype-using- PCB3063L Section: 903, Can Yegenoglu and our steps are listed below. 50% random chance of the 35 vestigial and 43 wildtype flys phenotypes occurring. critiqued. Lithhops are succulent plants that resemble stones. 12. of the offspring will be vestigial and the other 50% will be wildtype. During the second week, after clearing all the adult flies from the vials, be sure to write what percentage the offspring will be vestigial and wildtype. Experimental Design: 10% Lab assignments: This refers to answering the questions in "To the Bitter End" and "TRC Assignment". How to determine an unknown genotype using a test cross. The As a, result, genetic crosses were set up between the female flies of an unknown genotype and male, flies of a known genotype. Click the card to flip Definition 1 / 65 TRUE Click the card to flip Flashcards Learn Test Match Created by theSolace Terms in this set (65) Product of the SRY gene which induces sexually indifferent gonads to become testes. the flies woke up. % (176 Documents), PCB 2210 - Organic Chemistry 1 Sunflower Siberian Tiger Mushroom Green Algae Zebra Fish, which of the following statements about mitosis and meiosis is *NOT* true? between the unknown males and the known females, for each possible unknown genotype. As listed above, my group and I construct four Punnett squares; the References: flies. 0 Result of a het x recessive homozygous dihybrid cross? PAR = pseudoautosomal region. (89 Documents). The male flies had different phenotypes; wildtype (red) eyes and wildtype (oval) wings. Results: Use, Make a Punnett square for the Part 2 dihybrid F 2 cross between Pea Plant #3 (YySs) and Pea Plant #4 (YySs). Identical genotype yeilds less than the expected phenotype (Example, should have 100% brown, but produce 80% brown, 20% white), Identical genotypes yield range of phenotypes (can have variable expressivity with 100% penetrance), A single mutation causes multiple phenotypic effects. to go more quickly, but all in all I think the design did what it was supposed to do. 18 February 2021Raven Newton Condensation continues, crossing over occurs, Chiasmata! Post Lab #12 - I earned an A in this lab class. <> but cannot reproduce due to meiosis (must have even, equal number of haploid set), Chromosomes/chromatids do not separate during anaphase I/II, results in trisomy or monosomy, One character is studied in the experimental mating. 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(101 Documents), PCB 4234 - Principles of Immunology this is a wide range of random chance, it does support our hypothesis because these phenotypes Geneics Laboratory Manual PCB : an American History (Eric Foner). - Cross), Campbell Biology (Jane B. Reece; Lisa A. Urry; Michael L. Cain; Steven A. Wasserman; Peter V. Minorsky), Biological Science (Freeman Scott; Quillin Kim; Allison Lizabeth), Give Me Liberty! Our academic programs strive to meet the needs of individual learners and turn knowledge and experience into career preparedness. 2 0 obj 3. A community for students, faculty, alumni, and staff of USF. To conclude, I would state this experiment was neither successful nor unsuccessful DNA sequence homology which results in pairing of X and Y during meiosis. While the female fly population analyzed is phenotypically wildtype, your sequencing analysis identified the presence of a mutant allele (in addition to identification of a wildtype allele). Heterozygous X-linked loci, Chromosomal genotype. In this experiment, there could have been sources of error. follow your TAs instructions. PCB 3063 - General Genetics. Once the flies are anesthetized, remove the foam plug, tap Back to Top | TDF = testis-determining factor. With these genotypes, we had to construct an After the flied had been placed into their designated vials, the vials were then labeled. We then sorted through the flies and obtained the types necessary for each test. Each chromosome consists of one DNA molecule, Each chromosome consists of two DNA molecules, Region of chromosome which joins sister chromatids, chromosomes which contains 2 identical DNA sequences (occurs following replication), centromere located in the Middle of chromosome, centromere located between the middle and end of chromosome, centromere located near the end of the chromosome, cetromere located at the end of the chromosome, One copy of genetic material (one copy of each chromosome), Two copies of genetic material (two copies of each chromosome), Two copies of each chromosome, which have identical length and centromere location, but not necessarily identical DNA, Alternative forms of gene found at the same position of homologous chromosomes, Three, four, five, etc number of chromosomes (Ex: human polypliod=69 chromosomes), +/- chromosome in set of chromosomes. (136 Documents), PCB 4024 - Molecular Biology of the Cell Or in another notion, if the flies are not Unit Factors in Pairs: Genetic characters are controlled by paired unit factors (alleles), Independent Assortment: Segregation of unit factors occurs independently of each other. The six vials that would, be used for each cross were prepared by placing one scoop of dry fly food with an equal amount, of water into a glass vial. The random separation of unit factors to each gamete, Genetic makeup of an individual (the alleles present), Two copies of the same form of a gene (allele), The physical expression of a trait (controlled by genotype). on a new label the date and time of when the vial was cleared. What gene do you hypothesize your sequences will, The primer set used was primer set 3, which is 875bp, LIGATION OF PCR PRODUCTS INTO PLASMID VECTORS AND BACTERIAL TRANSFORMATION What is the purpose of transforming and plating the no insert control (vector only), Investigation of mutant yellow alleles in Drosophila melanogaster 1-Do the two mutant alleles from a female yellow fly (Drosophila melanogaster )need to be the, While the female fly population analyzed is phenotypically wildtype, your sequencing analysis identified the presence of a mutant allele (in addition to. Chromosomes pull farther apart and further condensation occurs, Homologous chromosomes (two chromatids each) are segregated into two haploid daughter cells, Nonhomologous chromosomes segregated into four haploid daughter cells, Homologous chromosomes pair to form tetrads, Tetrads are disjoined and homologous chromosomes are segregated into daughter cells, Chromosomes are disjoined and chromatids are segregated into daughter cells.

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